SOLUTION: how do you solve: log base 3 (x+4)+log base 3 (x-2)=3

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Question 605068: how do you solve:
log base 3 (x+4)+log base 3 (x-2)=3
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
log base 3 (x+4)+log base 3 (x-2) = 3
Combine the logs
log3%28%28x%2B4%29%2A%28x-2%29%29+=+3
FOIL
log3%28x%5E2%2B2x-8%29+=+3
the exponent equiv of logs
x%5E2+%2B+2x+-+8+=+3%5E3
:
x%5E2+%2B+2x+-+8+=+27
;
x%5E2+%2B+2x+-+8+-+27+=+0
:
x%5E2+%2B+2x+-+35+=+0
Factors to
(x+7)(x-5) = 0
Two solutions
x = -7
x = 5, since we are dealing with logs, only the positive solution is valid