SOLUTION: My Eemail address is staford904@aol.com. This is my math problem log base 9(x/y^4)^2. Is this the right way to solve 9(xy^4)^2= 9(xy^4(2))= 9xy^8

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: My Eemail address is staford904@aol.com. This is my math problem log base 9(x/y^4)^2. Is this the right way to solve 9(xy^4)^2= 9(xy^4(2))= 9xy^8       Log On


   

Question 604543: My Eemail address is staford904@aol.com. This is my math problem log base 9(x/y^4)^2. Is this the right way to solve 9(xy^4)^2= 9(xy^4(2))= 9xy^8
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Since you have provided an "expresson" rather than an "equation", there is nothing to "solve"!
However, you could simplify the given expression:
Log%5B9%5D%28x%2Fy%5E4%29%5E2 First, simplify the argument:
Log%5B9%5D%28x%5E2%2Fy%5E8%29 Now apply the "quotient rule" for logarithms: Log%5Bb%5D%28M%2FN%29+=+Log%5Bb%5D%28M%29-Log%5Bb%5D%28N%29 to get:
Log%5B9%5D%28x%5E2%29-Log%5B9%5D%28y%5E8%29 Now apply the "power rule":
2Log%5B9%5D%28x%29-8Log%5B9%5D%28y%29