SOLUTION: Hi, I know this question is odd because it isn't a cube equation and it isn't a quadratic equation, but it goes like this: {{{ x^3+6x=10 }}}
PLEASE help me! I really don't know w
Algebra ->
Inequalities
-> SOLUTION: Hi, I know this question is odd because it isn't a cube equation and it isn't a quadratic equation, but it goes like this: {{{ x^3+6x=10 }}}
PLEASE help me! I really don't know w
Log On
Question 604536: Hi, I know this question is odd because it isn't a cube equation and it isn't a quadratic equation, but it goes like this:
PLEASE help me! I really don't know what to do! Thank you so much. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
It's a cubic equation. It has no x^2 term but the x^3 makes it a cubic.
----------
--------------------
x = {q + [q^2 + (r-p^2)^3]^1/2}^1/3 + {q - [q^2 + (r-p^2)^3]^1/2}^1/3 + p
where
p = -b/(3a), q = p^3 + (bc-3ad)/(6a^2), r = c/(3a)
------------
a = 1, b = 0, c = 6, d = -10
-------------
p = 0
q = 5
r = 2
---------
x = {5 + [25 + 8]^1/2}^1/3 + {5 - [25 + 8]^1/2}^1/3
=
x =~ 1.300270977 the only real number solution