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Question 604353: The Vertex of the parabola below is at the point (6, 1.5) and the point (7, 3.5) is on the parabola. what is the equation of the parabola?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The Vertex of the parabola below is at the point (6, 1.5) and the point (7, 3.5) is on the parabola. what is the equation of the parabola?
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Assuming the parabola is opening upward (it could be to the right),
use the vertex-form:
(x-h)^2 = 4p(y-k)
Substitute for x,y,h,k and solve for "p":
(7-6)^2 = 4p(3.5-1.5)
1 = 4p(2)
4p = 1/2
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Equation:
(x-6)^2 = (1/2)(y-(3/2))
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y = 2[x^2-12x+36]+(3/2)
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y = 2x^2-24x+73.5
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Cheers,
Stan H.
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