SOLUTION: in triangle ABC, sin B= 1/3 , b= 15, c=9. find sin C

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Question 603774: in triangle ABC, sin B= 1/3 , b= 15, c=9. find sin C
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
From the Law of Sines we know:
sin%28B%29%2Fb+=+sin%28C%29%2Fc
Inserting the known values into this we get:
%281%2F3%29%2F15+=+sin%28C%29%2F9
Now we just solve for sin(C). Since this equation is a proportion we can use cross-multiplying to solve it:
%281%2F3%29%2A9+=+15%2Asin%28C%29
The left side simplifies:
3+=+15%2Asin%28C%29
Now we just divide both sides by 15:
3%2F15+=+sin%28C%29
which reduces to:
1%2F5+=+sin%28C%29