SOLUTION: How do I do the foil method on the following: (7x^3+5) (x^2+2)

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Question 602540: How do I do the foil method on the following:
(7x^3+5) (x^2+2)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%287x%5E3%2B5%29%28x%5E2%2B2%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%287x%5E3%29%2B5%29%28highlight%28x%5E2%29%2B2%29 Multiply the First terms:%287%2Ax%5E3%29%2A%28x%5E2%29=7%2Ax%5E5.


%28highlight%287x%5E3%29%2B5%29%28x%5E2%2Bhighlight%282%29%29 Multiply the Outer terms:%287%2Ax%5E3%29%2A%282%29=14%2Ax%5E3.


%287x%5E3%2Bhighlight%285%29%29%28highlight%28x%5E2%29%2B2%29 Multiply the Inner terms:%285%29%2A%28x%5E2%29=5%2Ax%5E2.


%287x%5E3%2Bhighlight%285%29%29%28x%5E2%2Bhighlight%282%29%29 Multiply the Last terms:%285%29%2A%282%29=10.


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So we have the terms: 7%2Ax%5E5, 14%2Ax%5E3, 5%2Ax%5E2, 10


7x%5E5%2B14x%5E3%2B5x%5E2%2B10 Now add every term listed above to make a single expression.


So %287x%5E3%2B5%29%28x%5E2%2B2%29 FOILs to 7x%5E5%2B14x%5E3%2B5x%5E2%2B10.


In other words, %287x%5E3%2B5%29%28x%5E2%2B2%29=7x%5E5%2B14x%5E3%2B5x%5E2%2B10 for all values of x.