SOLUTION: Find the equation of the tangent line to the curve y=e^3x at the point (0,1) Please Please Help!!

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Question 60232: Find the equation of the tangent line to the curve y=e^3x at the point (0,1)
Please Please Help!!
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the tangent line to the curve y=e^3x at the point (0,1)
To make the equation of a line, we need both a slope and a point. We find the slope of a tangent line by taking the derivative of the function and pluging in your point.
y=e%5E%283x%29
y'=e%5E%283x%29%2A%283%29
y'=3e%5E%283x%29
m=y'(0)=3e%5E%283%2A0%29
m=y'(0)=3e%5E%280%29
m=y'(0)=3%281%29
m=y'(0)=3
Since they gave us the y-intercept as a point we can use the slope-intercept formula to make the equation of the line: highlight%28y=mx%2Bb%29, m=slope, (0,b)=y-intercept.
m=3 and (0,b)=(0,1)
highlight%28y=3x%2B1%29
Happy Calculating!!!