SOLUTION: The pressure p exerted on a surface is the ratio of the force F on the surface to its Area A. find the pressure on a square patch (the length of each side of the square is 2.25in)
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-> SOLUTION: The pressure p exerted on a surface is the ratio of the force F on the surface to its Area A. find the pressure on a square patch (the length of each side of the square is 2.25in)
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Question 602176: The pressure p exerted on a surface is the ratio of the force F on the surface to its Area A. find the pressure on a square patch (the length of each side of the square is 2.25in) on a tank if the force on the patch is 37.4 pounds.
What I tried to do:
pressure p exerted= F(force)/ A (area) <----- formula Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The pressure p exerted on a surface is the ratio of the force F on the surface to its Area A. find the pressure on a square patch (the length of each side of the square is 2.25in) on a tank if the force on the patch is 37.4 pounds.
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p = f/A
p = 37.4/2.25^2
p =~ 7.39 lb/sq in
