SOLUTION: How do I solve 12e^(4x-3)=72

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Question 602054: How do I solve 12e^(4x-3)=72
Answer by lwsshak3(11628) About Me  (Show Source):
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How do I solve
12e^(4x-3)=72
e^(4x-3)=72/12=6
take log of both sides
(4x-3)lne=ln6
lne=1 (log of base=1)
4x-3=ln6
4x=ln6+3
x=(ln6+3)/4
x≈1.1979