SOLUTION: the diagonal of a rectangular room is 39 ft long. One wall measures 2 ft longer than the adjacent wall. find the dimensions of the room

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Question 601950: the diagonal of a rectangular room is 39 ft long. One wall measures 2 ft longer than the adjacent wall. find the dimensions of the room
Answer by Alan3354(69443) About Me  (Show Source):
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the diagonal of a rectangular room is 39 ft long. One wall measures 2 ft longer than the adjacent wall. find the dimensions of the room
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x%5E2+%2B+%28x%2B2%29%5E2+=+39%5E2
2x%5E2+%2B+4x+%2B+4+=+1521
2x%5E2+%2B+4x+-+1517+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 2x%5E2%2B4x%2B-1517+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%284%29%5E2-4%2A2%2A-1517=12152.

Discriminant d=12152 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-4%2B-sqrt%28+12152+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%284%29%2Bsqrt%28+12152+%29%29%2F2%5C2+=+26.5590275590413
x%5B2%5D+=+%28-%284%29-sqrt%28+12152+%29%29%2F2%5C2+=+-28.5590275590413

Quadratic expression 2x%5E2%2B4x%2B-1517 can be factored:
2x%5E2%2B4x%2B-1517+=+%28x-26.5590275590413%29%2A%28x--28.5590275590413%29
Again, the answer is: 26.5590275590413, -28.5590275590413. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B4%2Ax%2B-1517+%29

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Ignore the negative solution.
Check your posting for typos.