SOLUTION: Ok the problem I need help is as follows: log base 3 (x-8) + log base 3 (x-3) -log base 3 (x) So far I have tried (x-3)(x-8) = x^2-11x+24=1^3

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Ok the problem I need help is as follows: log base 3 (x-8) + log base 3 (x-3) -log base 3 (x) So far I have tried (x-3)(x-8) = x^2-11x+24=1^3       Log On


   



Question 601892: Ok the problem I need help is as follows:
log base 3 (x-8) + log base 3 (x-3) -log base 3 (x)
So far I have tried (x-3)(x-8) = x^2-11x+24=1^3
x^2-11x+25=100 right?
x(x^2-11x+25)=100
x^3-11x^2+25x=100
I know the answer is 12. I just don't know how to work this out.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28+3%2C+x-8+%29+%2B+log%28++3%2C+x-3+%29+-+log%28+3%2C+x+%29+
+log%28+3%2C+%28%28x-8%29%2A%28x-3%29%29%2Fx+%29+
+log%28+3%2C+%28%28+x%5E2+-+11x+%2B+24+%29+%2F+x+%29%29+
+log%28+3%2C+%28x+-+11+%2B+24%2Fx%29+%29+
There is no equals sign in the expression,
so you shouldn't have one in your answer.