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Question 601817: In a kennel, a cocker spaniel, a bulldog, and a greyhound all give birth to litters. the number of pups in the litters are consecutive integers (in the order: cocker spaniel, bulldog, greyhound.) The first integer increased by twice the second exceeds the third by 10. How many puppies does each dog have? Use 5-step method.
i have been working on this problem forever. this is word for word from my book. i just don't seem to understand.
thank you.
Found 2 solutions by Jacksonjacob, doll234:
Answer by Jacksonjacob(3)   (Show Source):
You can put this solution on YOUR website! This question is a reasoning question which can be solved by deep thinking.
Solution:
the type of animal in d kennel is 3, let dis 3 animals be represented by a, b, c. Let d first animal be a, & d second animal be b, & d third animal be c. From d question, let d 1st integer increased by twice the 2nd & exceed d 3rd by 10.
Step 2: since d 1st integer increased twice d 2nd = 2a : b
Step 3: since d 2nd exceed the third by 10 = 10b : c
Step 4: Recall that the question state the 1st is increased twice the second = 2*10=20a.
Step 5: Each dog will have 20 : 10 : 1.
Answer by doll234(2)  (Show Source):
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