SOLUTION: a mixture is prepared by mixing 50 grams of ethanol, 50 grams of water , and 5 grams sugar. what is the mass percent of each component in the mixture. how many grams of the

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Question 601549: a mixture is prepared by mixing 50 grams of ethanol, 50 grams of water , and 5 grams sugar.

what is the mass percent of each component in the mixture.
how many grams of the mixture should one take in order to have 1.5 grams sugar.
how many grams of the mixture should one take in order to have 10 grams of alcohol?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Total grams of mixture =
+50+%2B+50+%2B+5+=+105+
alcohol:
+50%2F105+=+.4762+
47.62%
water:
47.62%
sugar:
+5%2F105+=+.04762+
4.762%
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Let +x+ = grams of mixture that you take
+.04762x+=+1.5+
+x+=+1.5%2F.04762+
+x+=+31.5+
You must take 31.5 grams of the mixture
--------------------
+.4762x+=+10+
+x+=+10%2F.4762+
+x+=+21+
You must take 21 grams of the mixture