SOLUTION: Determine the vertex of the parabola. f(x) = x2 - 8x + 17

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Question 601470: Determine the vertex of the parabola.
f(x) = x2 - 8x + 17
Found 2 solutions by stanbon, lwsshak3:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the vertex of the parabola.
f(x) = x^2 - 8x + 17
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One way:
Complete the square:
x^2 - 8x + 16 + 17-16 = y
(x-4)^2 = y-1
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Vertex at (4,1)
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Another way:
Vertex occurs where x = -b/(2a) = 8/2 = 4
f(4) = 16-32+17 = 1
Vertex at (4,1)
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graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E2-8x%2B17%29
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Cheers,
Stan H.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the vertex of the parabola.
f(x) = x2 - 8x + 17
Complete the square
y = (x2 - 8x+16)+17-16
y = (x-4)^2+1
This is an equation of a parabola that opens upwards.
Its standard form: y=(x-h)^2+k (h,k)=(x,y) coordinates of the vertex
For given equation:y = (x-4)^2+1
vertex: (4,1)