SOLUTION: leg a: x+1 leg b: x+3 and the hypotnus is: 2 the square root of 5 i am at 3xsquared+6x+0=0, but i'm confused if you could solve to get the missing numbers?

Algebra ->  Test -> SOLUTION: leg a: x+1 leg b: x+3 and the hypotnus is: 2 the square root of 5 i am at 3xsquared+6x+0=0, but i'm confused if you could solve to get the missing numbers?      Log On


   

Question 601101: leg a: x+1
leg b: x+3
and the hypotnus is: 2 the square root of 5
i am at 3xsquared+6x+0=0, but i'm confused if you could solve to get the missing numbers?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I can't figure where you got unless you were just guessing. BTW, that is almost always a poor strategy. In any case, toss it out and start over.

Use Pythagoras.




Substitute what you were given:



Expand the binomials and square the constant.



Collect terms in the LHS



Divide by 2



Solve the factorable quadratic. Discard the negative root because it leads to the absurdity of negative measures of length. Calculate and


John

My calculator said it, I believe it, that settles it
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