SOLUTION: 4. X is normally distributed with mean 12 and standard deviation 4.
(a) (3 points)Find the probability that X will be more than 10.
p(X > 10) = 1 – p (X <= 10) = 0.69
(b) (3 poi
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-> SOLUTION: 4. X is normally distributed with mean 12 and standard deviation 4.
(a) (3 points)Find the probability that X will be more than 10.
p(X > 10) = 1 – p (X <= 10) = 0.69
(b) (3 poi
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Question 601093: 4. X is normally distributed with mean 12 and standard deviation 4.
(a) (3 points)Find the probability that X will be more than 10.
p(X > 10) = 1 – p (X <= 10) = 0.69
(b) (3 points) Find the probability that X will be less than 13.5
P(X < 13.5) = P(X < = 13.5) = 0.646
(c) (4 points) Find the probability that X will be between 10 and 14.5
P(10 < X < 14.5) = P(X < 14.5) - P(X < 10) = P(X <= 14.5) - P(X <= 10) –
0.7340145 - 0.3085375
(d) (4 points) Find a such that P(X
0.85 = 85% is the quantile.
P(X < 16.14573) =
P(X <= 16.14573) = 0.85
(e)(4 points) Find b such that P(X> b)=.25
P(X > b) = 1 - P(X <= b) = 0.25
= > 1 - 0.25 - P(X <= b) = 0;
0.75 - P(X <= b) = 0
0.75 = P(X <= b);
P(X <= b) = 0.75.
= > P(X <= 14.69796) = 0.75.
Did I do these right? Answer by jim_thompson5910(35256) (Show Source):
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