SOLUTION: 3x-5y=15x2
2x+3y=6x3
6x-10y=30......(1)
6x+9y=18.......(2)
subtracting (2) from (1) we get
-19y=12
y=-12/19
substituting value of y in equation (1) we get
3x-5y=15
3x-5(-1
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-> SOLUTION: 3x-5y=15x2
2x+3y=6x3
6x-10y=30......(1)
6x+9y=18.......(2)
subtracting (2) from (1) we get
-19y=12
y=-12/19
substituting value of y in equation (1) we get
3x-5y=15
3x-5(-1
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Question 600928: 3x-5y=15x2
2x+3y=6x3
6x-10y=30......(1)
6x+9y=18.......(2)
subtracting (2) from (1) we get
-19y=12
y=-12/19
substituting value of y in equation (1) we get
3x-5y=15
3x-5(-12/19)=15
3x=15-5(12/19)
3x=(19x15-5x12)/19
3x=(285-60)/19
3x=225/19
x=75/19
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