SOLUTION: 1. SQR(x+20)=x 2.SQR(10x)-(2)SQR(5x-25)=0 Solve each of the following. Check for extraneous solutions. What I know is; 1. x+20=x^2 That's as far as I know. I don't know

Algebra ->  Equations -> SOLUTION: 1. SQR(x+20)=x 2.SQR(10x)-(2)SQR(5x-25)=0 Solve each of the following. Check for extraneous solutions. What I know is; 1. x+20=x^2 That's as far as I know. I don't know       Log On


   

Question 600693: 1. SQR(x+20)=x
2.SQR(10x)-(2)SQR(5x-25)=0

Solve each of the following. Check for extraneous solutions.
What I know is; 1. x+20=x^2
That's as far as I know. I don't know how to check for extraneous solutions.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1. SQR(x+20)=x
2.SQR(10x)-(2)SQR(5x-25)=0

Solve each of the following. Check for extraneous solutions.
What I know is; 1. x+20=x^2
That's as far as I know. I don't know how to check for extraneous solutions.
------------
x+20=x^2
x%5E2+-+x+-+20+=+0
(x-5)*(x+4) = 0
x = -4
x = 5
-------
Check each answer to see if it works.
They both work --> no extraneous solutions.
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2.SQR(10x)-(2)SQR(5x-25)=0
SQR(10x) = (2)SQR(5x-25)
Square both sides
10x = 4*(5x - 25)
etc