Question 60055: Please show me how to do this. The book I am using doesn't provide enough example for me to understand what I am looking for. Thank you very much.
In 1990, 5.8% of job applicants who were tested for drugs failed the test. At the 0.01 level, test the claim that the failure is now lower if a random sample of 1,520 current job applicants results in 58 failures. Does the result suggest that fewer job applicants now use drugs? Give the z score to 2 decimal places and corresponding value of p to 4 decimal places. Also, do you conclude that fewer use drugs?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In 1990, 5.8% of job applicants who were tested for drugs failed the test. At the 0.01 level, test the claim that the failure is now lower if a random sample of 1,520 current job applicants results in 58 failures. Does the result suggest that fewer job applicants now use drugs? Give the z score to 2 decimal places and corresponding value of p to 4 decimal places. Also, do you conclude that fewer use drugs?
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p-hat=58/(1520)=0.038
C.V. = [0.038-0.058]/sqrt[(0.058*0.942)/1450]
= -3.258...
p=5.6106E-4
p=0.0005 to 4 decimal places
Comment: The TI-83 gives a p-value of 4.6727...E-4
Cheers,
Stan H.
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