SOLUTION: A basketball team consists of 11 players. In how many ways can a coach choose the five starting players, position of the player not being considered

Algebra ->  Permutations -> SOLUTION: A basketball team consists of 11 players. In how many ways can a coach choose the five starting players, position of the player not being considered      Log On


   



Question 600532: A basketball team consists of 11 players. In how many ways can a coach choose the five starting players, position of the player not being considered
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
C(n,r) = (n!)/(r!(n-r)!)

C(11,5) = (11!)/(5!*(11-5)!)

C(11,5) = (11!)/(5!*6!)

C(11,5) = (11*10*9*8*7*6!)/(5!*6!)

C(11,5) = (11*10*9*8*7)/(5!)

C(11,5) = (11*10*9*8*7)/(5*4*3*2*1)

C(11,5) = (55440)/(120)

C(11,5) = 462

So there are 462 ways.