Question 600532: A basketball team consists of 11 players. In how many ways can a coach choose the five starting players, position of the player not being considered
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! C(n,r) = (n!)/(r!(n-r)!)
C(11,5) = (11!)/(5!*(11-5)!)
C(11,5) = (11!)/(5!*6!)
C(11,5) = (11*10*9*8*7*6!)/(5!*6!)
C(11,5) = (11*10*9*8*7)/(5!)
C(11,5) = (11*10*9*8*7)/(5*4*3*2*1)
C(11,5) = (55440)/(120)
C(11,5) = 462
So there are 462 ways.
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