SOLUTION: (3y)^-1/2=6 if I square both sides and make 3y a fraction I get 1/3y=36 one over 3y equals 36 Now I am not sure what to do. do I take both sides by 3y and get 1=108y

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: (3y)^-1/2=6 if I square both sides and make 3y a fraction I get 1/3y=36 one over 3y equals 36 Now I am not sure what to do. do I take both sides by 3y and get 1=108y       Log On


   

Question 600393: (3y)^-1/2=6
if I square both sides and make 3y a fraction I get
1/3y=36
one over 3y equals 36
Now I am not sure what to do.
do I take both sides by 3y and get 1=108y
then 1/y=108?
How do I get y to not be a fraction?
Thank you!
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
%283y%29%5E%28-1%2F2%29+=6
This can be written as


%281%2F%283y%29%5E%281%2F2%29%29=6

Square both sides

1%2F3y+=+36

1%2F36+=+3y

1%2F108+=+y