SOLUTION: i need to simplify 5 over the square root of 3

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Question 600330: i need to simplify 5 over the square root of 3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
To rationalize the denominator, you simply multiply top and bottom of the fraction by the conjugate of the denominator. In general, the conjugate of sqrt%28x%29 is sqrt%28x%29 (the conjugate is itself)



5%2F%28sqrt%283%29%29 Start with the given expression.


%285%2Asqrt%283%29%29%2F%28sqrt%283%29%2Asqrt%283%29%29 Multiply top and bottom by sqrt%283%29


%285%2Asqrt%283%29%29%2F%28sqrt%283%2A3%29%29 Combine the roots.


%285%2Asqrt%283%29%29%2F%28sqrt%289%29%29 Multiply


%285%2Asqrt%283%29%29%2F%283%29 Take the square root of 9 to get 3.


So 5%2F%28sqrt%283%29%29 completely simplifies to %285%2Asqrt%283%29%29%2F%283%29


In other words, 5%2F%28sqrt%283%29%29=%285%2Asqrt%283%29%29%2F%283%29