You can put this solution on YOUR website! Solve the system of equations by substitution
y = x^2 + 2x - 2 and y - 3x + 4 <---you have a type-o here, I'm assuming that the - is supposed to be =. and
Se the two y's equal to each other: Set = to 0 Factor
(x-3)(x+2)=0 Set each parenthesis = to 0.
x-3=0 and x+2=0
x-3+3=0+3 and x+2-2=0-2
x=3 and x=-2
Substitute 3 in for x in the linear equation because it's easiest.
y=3(3)+4
y=9+4
y=13 One solution is (3,13)
Sustitute -2 in for x in the same equation:
y=3(-2)+4
y=-6+4
y=-2 The second solution is (-2,-2)
Graphically, you can see the two points of intersection:
Happy Calculating!!!
(