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| Question 599622:   Which is the equation of a circle that has a diameter with endpoints(1,3) and(-3,1) ?
 Answer by lwsshak3(11628)
      (Show Source): 
You can put this solution on YOUR website! Which is the equation of a circle that has a diameter with endpoints(1,3) and(-3,1) ? **
 Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
 center=midpoint of given endpoints of diameter:
 (-3+1)/2, (1+3)/2=-2/2,4/2=(-1,2)
 center(-1,2)
 solving for r (plug in coordinates of given point (1,3))
 (1+1)^2+(3-2)^2=r^2
 4+1=r^2
 r^2=5
 r=√5
 Equation of given circle:
 (x+1)^2+(y-2)^2=5
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