Question 599622: Which is the equation of a circle that has a diameter with endpoints(1,3) and(-3,1) ?
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Which is the equation of a circle that has a diameter with endpoints(1,3) and(-3,1) ?
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Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
center=midpoint of given endpoints of diameter:
(-3+1)/2, (1+3)/2=-2/2,4/2=(-1,2)
center(-1,2)
solving for r (plug in coordinates of given point (1,3))
(1+1)^2+(3-2)^2=r^2
4+1=r^2
r^2=5
r=√5
Equation of given circle:
(x+1)^2+(y-2)^2=5
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