SOLUTION: A rectangle is six times as long as it is wide. Determine the ratio of its area to its perimeter (A/P), in simplest form, if the width is w.

Algebra ->  Rectangles -> SOLUTION: A rectangle is six times as long as it is wide. Determine the ratio of its area to its perimeter (A/P), in simplest form, if the width is w.      Log On


   

Question 599404: A rectangle is six times as long as it is wide. Determine the ratio of its area to its perimeter (A/P), in simplest form, if the width is w.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
P = 2L+2W

L = 6W

P = 2(6W)+2W

P = 12W+2W

P = 14W

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A = LW

A = (6W)W

A = 6W^2

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A/P

(6W^2)/(14W)

(3W)/7


So the ratio A/P is (3W)/7


You can write the ratio as (3W)/7:1 or as 3W:7