SOLUTION: I found this problem on an SAT practice test
Given
a > b > 0
a^2 - b^2 = 12
list all posible values for
a - b =
Algebra ->
Systems-of-equations
-> SOLUTION: I found this problem on an SAT practice test
Given
a > b > 0
a^2 - b^2 = 12
list all posible values for
a - b =
Log On
You can put this solution on YOUR website! I found this problem on an SAT practice test
Given
a > b > 0
a^2 - b^2 = 12
list all posible values for
a - b =
(a+b)(a-b)=a^2-b^2
a-b = (a^2-b^2)/(a+b)=12/(a+b)
since a>b>0 and a^2 = b^2+12
a^2>12
a>sqrt(12)
hence a-b ...maximum value of a-b is 12/[sqrt(12)+] < sqrt (12)
since a could be any number > sqrt of 12
minimum value of a-b is >0
hence 0
