SOLUTION: Hello. I need help only on this question. Haerin told Jon to take a hike, so he did. He hiked for a total of 8 hours with an average speed of 5.5 km/h. Some of the time he walk

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Hello. I need help only on this question. Haerin told Jon to take a hike, so he did. He hiked for a total of 8 hours with an average speed of 5.5 km/h. Some of the time he walk      Log On

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Question 599198: Hello. I need help only on this question.
Haerin told Jon to take a hike, so he did. He hiked for a total of 8 hours with an average speed of 5.5 km/h. Some of the time he walked at a rate of 4 km/h, while the rest of the time he jogged at 10 km/h. For how many hours did he walk? For how many hours did he jog? How far did he jog? How far did he walk?
I tried the method of doing a chart/grid, same ones as these: http://www.purplemath.com/modules/distance.htm but I'm having troubles solving for this.
I just need the chart then I'll be happy solving the rest.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
He hiked for a total of 8 hours with an average speed of 5.5 km/h.
Some of the time he walked at a rate of 4 km/h, while the rest of the time he jogged at 10 km/h.
For how many hours did he walk? For how many hours did he jog?
How far did he jog? How far did he walk?
:
We can solve this easily with a system of equations
w = walking time
j = jogging time
:
total distance: 8 * 5.5 = 44 miles
:
w + j = 8
w = (8-j); use this for substitution
and
4w + 10j = 44
Replace w with (8-j)
4(8-j) + 10j = 44
32 - 4j = 44
-4j + 10j = 44 - 32
6j = 12
j = 12/6
j = 2 hrs jogging
and
8 - 2 = 6 hrs walking
:
2(10) = 20 mi jogging
6(4) = 24 mi walking