Question 598754:  1.'A' works twice as fast as 'B'. If both of them together take 6 days to complete the work, in how many days can 'B' alone complete the same? 
2.If 10 people working 8 hours a day, can complete a task in 24 days, how many people working 10 hours a day would be required to complete the same task in 16 days? 
3.’A’ alone can do a job in 25 days. He worked for 15 days and left. ‘B’ completed the remaining job in 10 days. If both of them work together after initial 15 days in how many more days would the job have been completed? 
4.If 10 men can complete a piece of work in 30 days how many men are requiredto complete the same job in 25 days? 
5.10men can complete a work in 18 days. After 6 days 5 more men joined. In how many days the remaining work would be completed? 
 Found 2 solutions by  josmiceli, vvnrichards: Answer by josmiceli(19441)      (Show Source): 
You can  put this solution on YOUR website! (1) 
You add the individual rates of working to get 
the rate of working together 
Let A's rate =   
Let B's rate  =   
Working together their rate is ( 1 job ) / ( 6 days ) 
given: 
  
  
By substitution: 
  
  
  
B can finish the job in 18 days working alone 
check: 
  
  
  
  
  
  
  
OK 
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(2) 
10 people working 8 hours a day, can complete a task in 24 days 
To finish in 1/3 of that time, each person works 3 times longer hours 
10 people working 24 hours a day take 8 days 
10 people working 12 hours a day take 16 days 
120 people working 1 hour a day take 16 days 
12 people working 10 hours a day take 16 days 
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(3) 
What fraction of the job does A do in 15 days? 
His rate is ( 1 job ) / ( 25 days ), so 
 fraction =   
That means   of the job is left 
‘B’ completed the remaining job in 10 days 
Let   = B's rate of working 
  
  
  
With both working together after the initial 15 days, 
  = rate woking together 
  
  
Let   = days to finish working together 
  
  
  
The job will be completed in 5 more days or 20 days altogether 
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(4) 
If 10 men take 30 days, 
then 60 men take 5 days 
then 12 men take 25 days 
( 1/5 as many men take 5 times longer ) 
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(5) 
10men can complete a work in 18 days 
In 1/3 of that time, 1/3 of the job gets done 
so, after 6 days, 2/3 of the job is left 
Now 5 men must do 2/3 of the job  
If 10men can complete a work in 18 days, 
5 men take 36 days to the job 
To do 2/3 of a job, 
number of days =   
The remaining work is completed in 24 days 
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 Answer by vvnrichards(3)      (Show Source): 
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