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Question 598640: Find the coordinates of the point that lies three fourths of the way from
(10, -8) to (6, 0)
a) (8, -4) b) (9, -2) c) (7, -2) d) (9, -6)
Found 2 solutions by stanbon, math-vortex:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the coordinates of the point that lies three fourths of the way from
(10, -8) to (6, 0)
a) (8, -4) b) (9, -2) c) (7, -2) d) (9, -6)
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Let (x,y) be that point:
x = 10 + (3/4)(6-10) = 10 + (3/4)(-4) = 10-3 = 7
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y = -8 + (3/4)(0-(-8)) = -8 + (3/4)(8) = -8+6 = -2
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Ans: (7.-2)
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Cheers,
Stan H.
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Answer by math-vortex(648)  (Show Source):
You can put this solution on YOUR website! Hi, there--
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One way to solve this problem is to find the midpoint between (10,-8) and (6,0). Then find the midpoint between THAT point and (6,0). [one-half plus one-half of one-half is 1/2 + 1/4 = 3/4.]
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[I] Find midpoint from(10,-8) to(6,0) by using the Midpoint Formula.
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The midpoint from (10,-8) to (6,0) is (8,-4).
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[II] Find the midpoint from (8,-4) to (6,0).
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The midpoint midway from (8,-4) to (6,0) to (7,-2).
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The answer is C.
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Best!
Ms.Figgy
math.in.the.vortex@gmail.com
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