Question 598152: Ok I'm haveing trouble with this one I try using one that had the a ship going down stream and back again but not sure if it was right.This is the problem.
On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the return trip downstream (with the current), her average speed was 3 mi/h. Find Rita's paddling speed in still water and the speed of the river's current.
This is what I tried: 3/2 or 1.5 mph, so the current is 1/2 the diference, so (3-1.5)/2 or 1.5/2=.75 mph for the current then Ritas paddleing speed is 3-.75=2.25 mph
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the return trip downstream (with the current), her average speed was 3 mi/h. Find Rita's paddling speed in still water and the speed of the river's current.
This is what I tried: 3/2 or 1.5 mph, so the current is 1/2 the diference, so (3-1.5)/2 or 1.5/2=.75 mph for the current then Ritas paddleing speed is 3-.75=2.25 mph
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The canoe's speed is the average = (2 + 3)/2 = 2.5 mi/hr
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The current is the difference = 3 - 2.5 = 0.5 mi/hr
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