You can put this solution on YOUR website! log(x+2) - log(2x+1)= logx
I am not sure what to do with the (-) and how it effects the rest of the problem.
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Remember, that when you subtract exponents (or logs) it is the same as dividing
We could write the problem:
log[] = log(x)
:
When the log of one expression = the log of another expression, the expressions are equal = x
Cross mult
:
x(2x+1) = x + 2
:
2x^2 + x = x + 2
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Subtract x from both sides
2x^2 = 2
:
x^2 = 2/2
:
x^2 = 1
:
x = 1
:
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Check by substitution:
log(1 + 2) - log(2 + 1) = log(1)
log(3) - log(3) = 0
What is the log of 1? It's 0, right?
