SOLUTION: Anne and Nancy use a metal alloy that is 13.2% copper to make jewelry. How many ounces of a 12% alloy must be mixed with a 15% alloy to form 55 ounces of the desired alloy?
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Question 597587: Anne and Nancy use a metal alloy that is 13.2% copper to make jewelry. How many ounces of a 12% alloy must be mixed with a 15% alloy to form 55 ounces of the desired alloy? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Anne and Nancy use a metal alloy that is 13.2% copper to make jewelry.
How many ounces of a 12% alloy must be mixed with a 15% alloy to form 55 ounces of the desired alloy?
:
Let x = amt of 15% alloy required
Resulting amt is to be 55 oz, therefore
(55-x) = amt of 12% alloy required
:
A typical mixture equation
.12(55-x) + .15x = .132(55)
6.6 - .12x + 15x = 7.26
-.12x + .15x = 7.26 - 6.6
,03x = .66
x = .66/.03
x = 22 oz of 15% alloy
then
55 - 22 = 33 oz 12% alloy
:
:
Check solutions
.12(33) + .15(22) = .132(55)
3.96 + 3.3 = 7.26
