SOLUTION: (x-1)(6ax+9x+4a+6)/(3x+2)(2ax-2a+3x-3)

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Question 59753This question is from textbook Intermediate Algebra
: (x-1)(6ax+9x+4a+6)/(3x+2)(2ax-2a+3x-3) This question is from textbook Intermediate Algebra

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-1%29%286ax%2B9x%2B4a%2B6%29%2F%283x%2B2%29%282ax-2a%2B3x-3%29

create a new variable called b
b = 2a + 3
2b = 4a + 6
3b = 6a + 9
substituting,
%28%28x-1%29%2A%283bx%2B2b%29%29%2F%28%283x%2B2%29%2A%28bx-b%29%29
b is a factor in the numerator and denominator
%28%28x-1%29%2Ab%283x%2B2%29%29%2F%28%283x%2B2%29%2Ab%28x-1%29%29
rewrite
%28b%2A%28x-1%29%2A%283x%2B2%29%29+%2F+%28b%2A%28x-1%29%2A%283x%2B2%29%29
All factors in the numerator cancel with all factors
in the denominator, so the expression = 1 answer