SOLUTION: a container has 5 blue balls, 7 red balls, and 4 green balls. if 3 balls are drawn, without replacement, what is the probability that all three will be green?
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-> SOLUTION: a container has 5 blue balls, 7 red balls, and 4 green balls. if 3 balls are drawn, without replacement, what is the probability that all three will be green?
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Question 597355: a container has 5 blue balls, 7 red balls, and 4 green balls. if 3 balls are drawn, without replacement, what is the probability that all three will be green? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! 5+7+4=16 total balls.
Combination=nCr=n!/((n-r)!r!)
4C3/16C3
=4/560
=1/140 the probability that all three will be green.
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Ed
