SOLUTION: The sum of three numbers is 4. The first number minus the second plus 5 times the third is 20. The third plus 5 times the first plus the second is -8. Find the numbers.

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: The sum of three numbers is 4. The first number minus the second plus 5 times the third is 20. The third plus 5 times the first plus the second is -8. Find the numbers.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 597196: The sum of three numbers is 4. The first number minus the second plus 5 times the third is
20. The third plus 5 times the first plus the second is -8. Find the numbers.

Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--
To solve this problem, we define variables for each number. Then we create a system of three equations in three variables. Finally, we solve the system of equations to find the three numbers.
.
[I] Define the variables.
Call the first number a.
Call the second number b.
Call the third number c.
.
.
[II] Create three equations.
.
The sum of the three numbers is 4. Using algebra, we write this relationship as
a%2Bb%2Bc=4
.
The first number minus the second plus 5 times the third is
20. In algebra we write this relationship as
a-b%2B5c=20
.
The third plus 5 times the first plus the second is -8. In algebra we write this relationship as
c%2B5a%2Bb=-8
.
Rewrite the third equation to have the variables in alphabetical order.
5a%2Bb%2Bc=-8
.
.
[III] Solve the system of equation.
I'll use the elimination and substitution methods here. You can also use a matrix to easily solve the system. Email me at my gmail address below if you want to see the matrix method, or repost this problem and ask for a matrix method solution.
.
a%2Bb%2Bc=4
a-b%2B5c=20
5a%2Bb%2Bc=-8
.
Add the 1st and 2nd equations together; solve to give an equation in a and c (NOTE: b+(-b)=0.)

.
Subtract 6a%2B6c=12 from 2a%2B6c=24. Solve for a.
-4a=12
a=-3
.
Substitute -3 for a in 2a%2B6c=24. Solve for c.
2%28-3%29%2B6c=24
%28-6%29%2B6c=24
6c=30
c=5
.
Substitute -3 for a and 5 for c in the first equation. Solve for b.
a%2Bb%2Bc=4
%28-3%29%2Bb%2B%285%29=4
2%2Bb=4
b=2
.
According to our algebra, the three numbers are -3, 2, and 5.
.
.
[IV] Check your work.
.
a%2Bb%2Bc=4
%28-3%29%2B2%2B5=4
4=4
Check!
.
a-b%2B5c=20
%28-3%29-2%2B5%285%29=20
-5%2B25=20
20=20
Bingo!
.
c%2B5a%2Bb=-8
%285%29%2B5%28-3%29%2B%282%29=-8
5-15%2B2=-8
-8=-8
Presto!
.
That's it! Feel free to email me via gmail with any questions about the solution.
.
Ms.Figgy
math.in.the.vortex@gmail.com