Question 597191: The release of
fluorocarbons used in household sprays destroys ozone layer in
the upper atmosphere. Suppose the amount of ozone is given by P = Ce-.0025t, where t is
measured in years. How long will it take for 70% of the ozone to disappear? (Round to the
nearest yr.)
is it like c=100 and then i solve for t and P= 70%
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose the amount of ozone is given by P = Ce-.0025t, where t is
measured in years. How long will it take for 70% of the ozone to disappear? (Round to the nearest yr.)
is it like c=100 and then i solve for t and P= 70%
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The statement of the problem seems to imply that
P is the percent of ozone and C is the current amount.
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If that is true, solve:
0.70C = C*e^-0.0025t
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e^-0.0025t = 0.70
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Take the log to get:
-0.0025t = ln0.70 = -0.35667...
The t = 142.7 years
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Cheers,
Stan H.
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