SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Algebra ->
Expressions-with-variables
-> SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Log On
Question 59719This question is from textbook
: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. This question is from textbook
You can put this solution on YOUR website! L=2W+2
2L+2W=52
2(2W+2)+2W=52
4W+4+2W=52
6W=52-4
6W=48
W=48/6
W=8 THE WIDTH IS 8 CM. THEN
L=2*8+2
L=16+2
L=18 THE LENGTH IS 18 CM.
PROOF
2*18+2*8=52
36+16=52
52=52