SOLUTION: (x+5)(3x-1)+13=0 2x^2+3x=20
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Question 59698
:
(x+5)(3x-1)+13=0
2x^2+3x=20
Answer by
checkley71(8403)
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(x+5)(3x-1)+13=0
3x^2+15x-x-5+13=0
3x^2+14x+8=0
(3x+2)(x+4)=0
3x+2=0
3x=-2
x=-2/3 solution
x+4=0
x=-4 solution
2x^2+3x=20
2x^2+3x-20=0
(2x-5)(x+4)=0
2x-5=0
2x=5
x=2/5 solution
x+4=0
x=-4 solution