SOLUTION: find the complex zeros of the polynomial function write f in the factored form. x^3+216 so far I have done: x^3 + 6^3 (a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36) quadratic

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: find the complex zeros of the polynomial function write f in the factored form. x^3+216 so far I have done: x^3 + 6^3 (a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36) quadratic      Log On


   

Question 596411: find the complex zeros of the polynomial function write f in the factored form. x^3+216
so far I have done:

x^3 + 6^3

(a+b)(a^2-ab+b^2) = (x+6)(x^2-6x+36)

quadratic formula: -b plus or minus square root (b^2 - 4 * a * c)/2

6 +- square root (36 - 144)/2

I am confused on the simplified answer not the math in general so would I leave
6 +- square root 108 in that form divided by 2 or what?

Answer by dfrazzetto(283) About Me  (Show Source):
You can put this solution on YOUR website!
108 has a perfect square as a factor
108 = 36 * 3
so sqrt%28-108%29 = sqrt%28108%29%2Asqrt%28-1%29 = i%2Asqrt%2836%2A3%29 = i%2Asqrt%2836%29%2Asqrt%283%29 = 6i%2Asqrt%283%29


%286+%2B-+6i%2Asqrt%283%29%29%2F2


3 +- 3i*sqrt(3)