Question 596338: I am having trouble figuring out how to find the domain , range, horizontal asymptote, intercept coordinates and additional points on the graph for the problem and would appreciate any assistance in figuring it out.
F(x)= log2 (x+1) +2
thanks in advance, and appreciate your time.
-Shae
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! logarithms are not defined for negative arguments, so the domain is all real numbers greater than -1
the range is all real numbers
there is no horizontal asymptote, but there is a vertical asymptote at x = -1
___as the argument of a logarithm approaches zero, the logarithm approaches negative infinity
when x = 0 , F(x) = 2 (y-intercept) ___ log2(0+1) + 2 = 0 + 2 = 2
when x = -3/4 , F(x) = 0 (x-intercept) ___ log2(-3/4 + 1) + 2 = log2(1/4) + 2 = log2(2^-2) + 2 = -2 + 2 = 0
the graph at two different scales, to show intercepts and shape
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