You can put this solution on YOUR website! Let A be an angle in which cosA = square root 2/2
What is cot A
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A could be in Q1 or Q4.
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Since cos = x/r = Sqrt(2)/2, x = sqrt(2) and r = 2
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Then y = sqrt(r^2-x^2) = sqrt(4+2) = sqrt(6) in Q1 and -sqrt(6) in Q4.
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In Q1: cot(A) = x/y = sqrt(2)/sqrt(6)
In Q4: cot(A) = x/y = -[sqrt(2)/sqrt(6)]
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Cheers,
Stan H.