SOLUTION: if cosx=4/5 find sinx for 0<=x<2pie

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Question 596160: if cosx=4/5 find sinx for 0<=x<2pie
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sin^2(x)+cos^2(x) = 1

sin^2(x)+(4/5)^2 = 1

sin^2(x)+16/25 = 1

sin^2(x) = 1-16/25

sin^2(x) = 9/25

sin(x) = sqrt(9/25)

sin(x) = 3/5