SOLUTION: Please help me solve this equation: 8x^6y^2/2x^3y^4 i Know that you subtract the exponents so it becomes: 4x^3/y^-2 then i THINK you're suppose to bring the n

Algebra ->  Exponents -> SOLUTION: Please help me solve this equation: 8x^6y^2/2x^3y^4 i Know that you subtract the exponents so it becomes: 4x^3/y^-2 then i THINK you're suppose to bring the n      Log On


   

Question 596096: Please help me solve this equation: 8x^6y^2/2x^3y^4
i Know that you subtract the exponents so it becomes: 4x^3/y^-2
then i THINK you're suppose to bring the negative exponent up, turning into:
4x^3 y^2
but i am not to sure, please help me.
Found 2 solutions by jim_thompson5910, math-vortex:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You are very close. You just made one minor mistake.

When you subtract exponents, it's all done in reference to the numerator. Basically, you should have

4x%5E3y%5E%28-2%29

Now you flip the fraction y%2F1 to get 1%2Fy to make the exponent negative giving you the final answer

%284x%5E3%29%2F%28y%5E2%29

Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--
You are close...subtracting the exponents when you divide is correct.
.
%288x%5E6%2Ay%5E2%29%2F%282x%5E3%2Ay%5E4%29
.
As long as you leave the y-term in the denominator, the exponent is positive.
%284x%5E3%29%2F%28y%5E2%29
.
If you move it to the numerator, it becomes a negative exponent because 2-4=-2.
4x%5E3%2Ay%5E-2
.
Hope this helps! Feel free to email if you still have questions about this.
.
Ms.Figgy
math.in.the.vortex@gmail.com