SOLUTION: Kent drives his Mazda 270 miles in the same time Dave drives his Honda 250 miles. If Kent averages 4 miles per hour faster than Dave, find their speeds. Thank you, Trudy

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Question 596046: Kent drives his Mazda 270 miles in the same time Dave drives his Honda 250 miles. If Kent averages 4 miles per hour faster than Dave, find their speeds.
Thank you, Trudy

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Distance equals rate times time, therefore time equals distance divided by rate.

Let represent the slower guy's rate then must be the faster guy's rate. The time's are equal, so let represent the time.

Slow guy's trip:

Fast guy's trip:

Since we can say:



Solve for , then compute

John

My calculator said it, I believe it, that settles it
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