You can put this solution on YOUR website! 100 calculators; 2 are defective.
I buy 8; what is the probability that I will get a defected one.
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P(at least one defective) = 1 - P(no defective)
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= 1 - 98C8/100C8
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= 1 - 0.8457
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= 0.1543
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Cheers,
Stan H.
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