SOLUTION: The perimeter of a rectangle is 48 inches. Find its length if its width is 5 inches.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 48 inches. Find its length if its width is 5 inches.      Log On


   



Question 595625: The perimeter of a rectangle is 48 inches. Find its length if its width is 5 inches.
Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 48 inches. Find its length if its width is 5 inches.
---------------------------------------------------------------
Hi, there--
.
Let's define some variables so we can write a formula for the perimeter.
Let's have L be the length and W be the width.
.
The perimeter is the distance around the rectangle, 48 inches. Remember that a rectangle has two equal lengths and two equal widths. We can call those 2L and 2W. Altogether, they add to 48 inches.
.
Then, the formula for the perimeter of your rectangle is
2L%2B2W=48
.
We know that the length of the rectangle is 5 inches. Substitute 5 for L in the formula.
2%285%29%2B2W=48
.
Now we simplify and solve for W.
10%2B2W=48
.
Subtract 10 from both sides.
2W=38
.
Divide both sides by 2.
W=19
.
According to our algebra, the width is 19 inches. We need to go back and check our work to make sure we did not make a mistake. Do our two widths and two lengths add up to 48 inches?
19%2B19%2B5%2B5=48
48=48
Bingo!!!
.
That's it. Feel free to email if any part of the explanation does not make sense.
.
Ms.Figgy
math.in.the.vortex@gmail.com