Question 59558: Here is my problem. I attempte to solve it but I don't understand how to report the answer right.
Find the margin of error that correspond to the given values of n(times) and x( successes) and the degree of confidence:n=1400,x=420 and 95%.
So, za/2 * square root of (pq/n)
= 1.96 sqrt[(.3)(.7)/1400]
= 1.96 sqrt(0.012247
= .000294? How do I report answer to 3 decimal places of precision?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the margin of error that correspond to the given values of n(times) and x( successes) and the degree of confidence:n=1400,x=420 and 95%.
So, za/2 * square root of (pq/n)
= 1.96 sqrt[(.3)(.7)/1400]
= 1.96 sqrt[0.012247...)
= 1.96*0.1107
=0.21697
=0.217 (answer to 3 decimal places of precision)
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However, if the result had been 0.000294 and you were told
to answer to 3 decimal places, the answer would have to be
0.0
Cheers,
Stan H.
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