SOLUTION: If shop #1 charges a $45 fee plus $75 per hour repair charge and Shop #2 charges a $60 fee plus $65 per hour repair fee. How many repair hours before shop #2 is less expensive tha

Algebra ->  Human-and-algebraic-language -> SOLUTION: If shop #1 charges a $45 fee plus $75 per hour repair charge and Shop #2 charges a $60 fee plus $65 per hour repair fee. How many repair hours before shop #2 is less expensive tha      Log On


   



Question 595515: If shop #1 charges a $45 fee plus $75 per hour repair charge and Shop #2 charges a $60 fee plus $65 per hour repair fee. How many repair hours before shop #2 is less expensive than shop #1?
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
45+75x=60+65x
75x-65x=60-45
10x=15
x=15/10
x=1.5 hrs