SOLUTION: Solve for X:
logbase6 of X + logbase6 of(3x-5)= logbase6 of 2
(by logbase6of..i mean log and then 6 as the little exponent at the bottom and then the other number as the nu
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-> SOLUTION: Solve for X:
logbase6 of X + logbase6 of(3x-5)= logbase6 of 2
(by logbase6of..i mean log and then 6 as the little exponent at the bottom and then the other number as the nu
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Question 595494: Solve for X:
logbase6 of X + logbase6 of(3x-5)= logbase6 of 2
(by logbase6of..i mean log and then 6 as the little exponent at the bottom and then the other number as the number that goes beside the exponent...hope that helps...:))
Thank you!!!! Answer by mamiya(56) (Show Source):
You can put this solution on YOUR website! logbase6 of X + logbase6 of(3x-5)= logbase6 of x(3x-5)
--> logbase6 of x(3x-5) = logbase6 of 2
--> x(3x-5) = 2
--> 3x^2 -5x -2 =0
Using the quadratic formula, we get
X = (5-qsrt(5^2-4(-2)(3)))/2(3)
= (5-qsrt(25+24))/6
= (5-7)/6
= -2/6 = -1/3
X = (5+qsrt(5^2-4(-2)(3)))/2(3)
= (5+qsrt(25+24))/6
= (5+7)/6
= 2
so the answer are -1/3 and 2
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